UNIT 1

Atomic Structure and Properties

Learn the fundamental structure of atoms, elements, and isotopes and understand how atomic properties influence chemical behavior.

Topics

Moles and Molar Mass

The mole is a fundamental unit used in chemistry to describe an amount of substance. It connects the microscopic world of particles to measurable quantities such as mass.

What Is a Mole?

A mole is a counting unit, much like a dozen. While one dozen represents 12 objects, one mole represents 6.022 × 1023 particles.

Avogadro’s number: One mole of any substance contains 6.022 × 1023 representative particles.

Representative particles may be atoms, molecules, ions, or formula units, depending on the substance.

1 mol = 6.022 × 1023 particles

Converting Between Moles and Particles

To convert from moles to particles, multiply by Avogadro’s number. To convert from particles to moles, divide by Avogadro’s number.

Example: Moles to Particles

How many molecules are present in 2.00 moles of H2O?

2.00 mol × 6.022 × 1023 molecules 1 mol = 1.20 × 1024 molecules

What Is Molar Mass?

Molar mass is the mass of one mole of a substance. It is measured in grams per mole, or g/mol. The molar mass of an element is numerically equal to its atomic mass on the periodic table.

Example: Finding Molar Mass

Calculate the molar mass of H2O.

2(1.008 g/mol) + 16.00 g/mol = 18.02 g/mol

Converting Between Grams and Moles

Molar mass is used as a conversion factor between grams and moles. To convert grams to moles, divide by the molar mass. To convert moles to grams, multiply by the molar mass.

Moles = Mass in grams ÷ Molar mass

Example: Grams to Moles

How many moles are present in 36.04 grams of H2O?

The molar mass of H2O is 18.02 g/mol.

36.04 g × 1 mol H2O 18.02 g H2O = 2.000 mol H2O

Practice Questions

Try each problem before opening the solution.

Question 1

How many molecules are present in 0.500 mol of CO2?

Show solution

Multiply the number of moles by Avogadro’s number:

0.500 mol × 6.022 × 1023 molecules 1 mol = 3.01 × 1023 molecules

Question 2

How many moles are present in 44.01 g of CO2?

Show solution

The molar mass of CO2 is 44.01 g/mol.

44.01 g × 1 mol 44.01 g = 1.000 mol CO2

Question 3

What mass of Na contains 3.011 × 1023 atoms?

Show solution

First, convert atoms to moles:

3.011 × 1023 atoms × 1 mol 6.022 × 1023 atoms = 0.5000 mol Na

Next, multiply by the molar mass of sodium:

0.5000 mol Na × 22.99 g Na 1 mol Na = 11.50 g Na
VIDEO EXPLANATION

Watch: Moles and Molar Mass

Watch a worked example explaining how to convert between moles, particles, and mass.

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Mass Spectrometry

Mass spectrometry is an experimental technique used to identify the isotopes of an element and measure their relative abundances. (Remember an isotope is the same element with a different number of neutrons in the nucleus) The resulting data can be displayed in a mass spectrum.

Key idea: A mass spectrum provides evidence about which isotopes are present in a sample and how common each isotope is.

Reading a Mass Spectrum

Each vertical peak in a mass spectrum represents an isotope detected in the sample. The position and height of each peak provide different information about that isotope.

How to interpret a peak: First read its position on the horizontal axis to determine the isotope’s approximate mass. Then read its height to determine the isotope’s relative abundance.
Mass spectrum with a 69 percent peak at mass 62g and a 31 percent peak at mass 64g
This hypothetical element has two isotopes. The isotope at m = 62 is more abundant than the isotope at m = 64.

Calculating Average Atomic Mass

The atomic mass shown on the periodic table is a weighted average of an element’s naturally occurring isotopes. This means that an isotope with a greater abundance has a greater effect on the element’s average atomic mass.

Important: Average atomic mass is not usually the mass of one individual atom. It is an average that accounts for the masses and abundances of all naturally occurring isotopes of an element.

Steps for Finding Average Atomic Mass

  1. Convert each percentage abundance into a decimal by dividing it by 100.
  2. Multiply the mass of each isotope by its decimal abundance.
  3. Add the results for all the isotopes.
Average atomic mass = (isotope 1 mass × decimal abundance) + (isotope 2 mass × decimal abundance)

Example: Finding Average Atomic Mass

A hypothetical element has two naturally occurring isotopes:

  • An isotope with a mass of 62 amu and an abundance of 69.0%
  • An isotope with a mass of 64 amu and an abundance of 31.0%

First, convert the percentage abundances into decimals:

69.0% ÷ 100 = 0.690

31.0% ÷ 100 = 0.310

Next, multiply each isotopic mass by its decimal abundance:

62 amu × 0.690 = 42.78 amu

64 amu × 0.310 = 19.84 amu

Finally, add the two contributions:

42.78 amu + 19.84 amu = 62.62 amu

The average atomic mass is 62.62 amu. This value is closer to 62 amu than to 64 amu because the isotope with a mass of 62 amu is more abundant.

Mass Spectrometry Practice

Use the mass spectrum and average atomic mass concepts from this lesson to answer the following questions.

Question 1: Interpreting a Spectrum

A mass spectrum contains a peak at an isotopic mass of 48 amu with a relative abundance of 74% and another peak at 50 amu with a relative abundance of 26%.

Which isotope is more abundant, and what evidence from the spectrum supports your answer?

Show solution

The isotope with a mass of 48 amu is more abundant.

Its peak represents 74% of the sample, while the peak for the 50 amu isotope represents only 26%. Therefore, the peak at 48 amu would be taller.

Question 2: Calculating Average Atomic Mass

A hypothetical element has two naturally occurring isotopes:

  • 70 amu with an abundance of 65.0%
  • 72 amu with an abundance of 35.0%

Calculate the average atomic mass of the element.

Show solution

First, convert the percentages to decimals:

65.0% ÷ 100 = 0.650

35.0% ÷ 100 = 0.350

Multiply each isotopic mass by its decimal abundance:

70 amu × 0.650 = 45.50 amu

72 amu × 0.350 = 25.20 amu

Add the two contributions:

45.50 amu + 25.20 amu = 70.70 amu

The element’s average atomic mass is 70.70 amu.

Question 3: Reasoning from an Average

A hypothetical element has two isotopes with masses of 24 amu and 26 amu. Its average atomic mass is 25.6 amu.

Without calculating exact abundances, which isotope must be more abundant? Explain your reasoning.

Show solution

The isotope with a mass of 26 amu must be more abundant.

The average atomic mass of 25.6 amu is much closer to 26 amu than to 24 amu. A weighted average is pulled toward the isotope with the greater abundance.

VIDEO EXPLANATION

Watch: Mass Spectrometry

Watch a worked example explaining mass spectrometry and how to interpret a mass spectrum graph

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Atomic Structure

Every atom contains protons, neutrons, and electrons. The number and arrangement of these particles determine an atom’s identity, mass, charge, and chemical behavior.

Subatomic Particles

Particle Charge Approximate Mass Location
Proton +1 1 amu Nucleus
Neutron 0 1 amu Nucleus
Electron −1 Approximately 0 amu Outside the nucleus
Atomic number: the number of protons in an atom. The number of protons determines the identity of the element.

Mass number: the total number of protons and neutrons in an atom.
Mass number = protons + neutrons
Neutrons = mass number − atomic number

Isotopes

Isotopes are atoms of the same element that contain different numbers of neutrons. Because isotopes of an element have the same number of protons, they have the same atomic number. Their different numbers of neutrons give them different mass numbers.

Example: Carbon-14

Carbon has an atomic number of 6, so every carbon atom contains 6 protons. Carbon-14 has a mass number of 14.

Neutrons = 14 − 6 = 8 neutrons

A neutral carbon-14 atom therefore contains 6 protons, 8 neutrons, and 6 electrons.

Ions

An ion forms when an atom gains or loses electrons. The number of protons does not change when an ion forms because changing the number of protons would change the identity of the element.

Charge = number of protons − number of electrons

Example: Aluminum Ion

Aluminum has an atomic number of 13. An Al3+ ion still has 13 protons, but it has lost 3 electrons.

13 protons − 10 electrons = +3 charge

Electron Configuration

Electrons occupy energy levels and sublevels outside the nucleus. An electron configuration describes how the electrons in an atom are distributed among these energy levels and sublevels.

Electrons generally fill lower-energy orbitals before filling higher-energy orbitals.

Sodium has 11 electrons. Its electron configuration is:

Na: 1s2 2s2 2p6 3s1

The superscripts add to 11, matching the total number of electrons in a neutral sodium atom. The electron in the 3s sublevel is sodium’s outermost, or valence, electron.

Periodic Trends

The arrangement of the periodic table reflects patterns in atomic structure. These patterns help predict how strongly atoms attract electrons and how easily their electrons can be removed.

Trend Across a Period → Down a Group ↓
Atomic radius Generally decreases Generally increases
Ionization energy Generally increases Generally decreases
Electronegativity Generally increases Generally decreases

Understanding the Periodic Trends

Periodic trends can be explained by the attraction between the positively charged nucleus and negatively charged electrons. This attraction is affected by nuclear charge, distance from the nucleus, and shielding from inner electrons.

Coulombic attraction: The attraction between the nucleus and an electron becomes stronger when the nuclear charge increases or when the electron is closer to the nucleus. The attraction becomes weaker when the electron is farther from the nucleus or is shielded by inner electrons.

Atomic Radius

Atomic radius is a measure of the size of an atom. It represents the approximate distance from the nucleus to the outermost occupied region of the electron cloud.

Across a period: Atomic radius generally decreases from left to right. The number of protons increases, but the added electrons enter the same principal energy level. Because shielding does not increase greatly, the stronger nuclear charge pulls the electrons closer to the nucleus.

Down a group: Atomic radius generally increases. Each step down introduces another occupied principal energy level. The valence electrons are farther from the nucleus and experience more shielding from inner electrons.

Ionization Energy

Ionization energy is the energy required to remove an electron from a gaseous atom.

Across a period: Ionization energy generally increases from left to right. The increasing nuclear charge and decreasing atomic radius create a stronger attraction between the nucleus and the valence electrons. More energy is therefore required to remove an electron.

Down a group: Ionization energy generally decreases. The valence electrons are farther from the nucleus and are shielded by more inner electrons. This weakens their attraction to the nucleus, making them easier to remove.

Electronegativity

Electronegativity describes an atom’s ability to attract shared electrons toward itself when it is chemically bonded to another atom.

Across a period: Electronegativity generally increases from left to right. The increasing nuclear charge and decreasing atomic radius allow the nucleus to attract shared electrons more strongly.

Down a group: Electronegativity generally decreases. Greater distance and increased shielding weaken the nucleus’s attraction for shared electrons.

Remember the general patterns: Atomic radius increases toward the bottom-left of the periodic table. Ionization energy and electronegativity generally increase toward the top-right. These are general trends, and some elements have exceptions caused by their particular electron configurations.

Atomic Structure Practice

Try each question before opening its solution.

Question 1: Counting Subatomic Particles

An atom has an atomic number of 17 and a mass number of 37. How many protons, neutrons, and electrons are present in the neutral atom?

Show solution

The atomic number gives the number of protons:

Protons = 17

A neutral atom has the same number of electrons as protons:

Electrons = 17

Subtract the atomic number from the mass number to find the number of neutrons:

Neutrons = 37 − 17 = 20

Question 2: Determining an Ion’s Charge

An ion contains 12 protons and 10 electrons. What is its charge?

Show solution
Charge = 12 − 10 = +2

The ion has a 2+ charge. It has two more protons than electrons.

Question 3: Electron Configuration

How many total electrons are represented by the following electron configuration?

1s2 2s2 2p6 3s2 3p3
Show solution

Add the superscripts:

2 + 2 + 6 + 2 + 3 = 15 electrons

A neutral atom with 15 electrons also has 15 protons, which identifies it as phosphorus.

Question 4: Periodic Trends

Potassium is located below sodium in the periodic table. Which element is expected to have the larger atomic radius? Explain your reasoning.

Show solution

Potassium has the larger atomic radius. Potassium has an additional occupied energy level, placing its valence electron farther from the nucleus.

VIDEO EXPLANATION

Watch: Atomic Structure

Watch an explanation of subatomic particles, isotopes, ions, and electron configurations.

Watch on TikTok →